Consejos
JAVA
Si una solución en Java te da Timeout puede ser por culpa de que java.util.Scanner es muy lento.
En JOEL aconsejamos usar el Fast Input / Output
desarrollado por Adrian Moreno, que está testeado exhaustivamente en nuestros problemasimport java.util.*;
import java.io.*;
public class Main {
static final int MOD = 1000000007;
static InputReader in = new InputReader(System.in);
static BufferOutput out = new BufferOutput();
public static void main(String[] args) throws IOException {
}
static class BufferOutput {
private DataOutputStream dout;
final private int BUFFER_SIZE = 1 << 16;
private byte[] buffer;
private int pointer = 0;
public BufferOutput() {
buffer = new byte[BUFFER_SIZE];
dout = new DataOutputStream(System.out);
}
public BufferOutput(OutputStream out) {
buffer = new byte[BUFFER_SIZE];
dout = new DataOutputStream(out);
}
public void writeBytes(byte arr[]) throws IOException {
int bytesToWrite = arr.length;
if (pointer + bytesToWrite >= BUFFER_SIZE) {
flush();
}
for (int i = 0; i < bytesToWrite; i++) {
buffer[pointer++] = arr[i];
}
}
public void writeString(String str) throws IOException {
writeBytes(str.getBytes());
}
public void flush() throws IOException {
dout.write(buffer, 0, pointer);
dout.flush();
pointer = 0;
}
public void close() throws IOException{
dout.close();
}
}
static class InputReader {
private InputStream in;
private byte[] buffer = new byte[1024];
private int curbuf;
private int lenbuf;
public InputReader(InputStream in) {
this.in = in;
this.curbuf = this.lenbuf = 0;
}
public String nextLine() {
StringBuilder sb = new StringBuilder();
int b = readByte();
while (b != 10) {
sb.appendCodePoint(b);
b = readByte();
}
if (sb.length() == 0)
return "";
return sb.toString().substring(0, sb.length() - 1);
}
public boolean hasNextByte() {
if (curbuf >= lenbuf) {
curbuf = 0;
try {
lenbuf = in.read(buffer);
} catch (IOException e) {
throw new InputMismatchException();
}
if (lenbuf <= 0)
return false;
}
return true;
}
private int readByte() {
if (hasNextByte())
return buffer[curbuf++];
else
return -1;
}
private boolean isSpaceChar(int c) {
return !(c >= 33 && c <= 126);
}
private void skip() {
while (hasNextByte() && isSpaceChar(buffer[curbuf]))
curbuf++;
}
public boolean hasNext() {
skip();
return hasNextByte();
}
public String next() {
if (!hasNext())
throw new NoSuchElementException();
StringBuilder sb = new StringBuilder();
int b = readByte();
while (!isSpaceChar(b)) {
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
public int nextInt() {
if (!hasNext())
throw new NoSuchElementException();
int c = readByte();
while (isSpaceChar(c))
c = readByte();
boolean minus = false;
if (c == '-') {
minus = true;
c = readByte();
}
int res = 0;
do {
if (c < '0' || c > '9')
throw new InputMismatchException();
res = res * 10 + c - '0';
c = readByte();
} while (!isSpaceChar(c));
return (minus) ? -res : res;
}
public long nextLong() {
if (!hasNext())
throw new NoSuchElementException();
int c = readByte();
while (isSpaceChar(c))
c = readByte();
boolean minus = false;
if (c == '-') {
minus = true;
c = readByte();
}
long res = 0;
do {
if (c < '0' || c > '9')
throw new InputMismatchException();
res = res * 10 + c - '0';
c = readByte();
} while (!isSpaceChar(c));
return (minus) ? -res : res;
}
public double nextDouble() {
return Double.parseDouble(next());
}
public int[] nextIntArray(int n) {
int[] a = new int[n];
for (int i = 0; i < n; i++)
a[i] = nextInt();
return a;
}
public long[] nextLongArray(int n) {
long[] a = new long[n];
for (int i = 0; i < n; i++)
a[i] = nextLong();
return a;
}
public char[][] nextCharMap(int n, int m) {
char[][] map = new char[n][m];
for (int i = 0; i < n; i++)
map[i] = next().toCharArray();
return map;
}
}
}
Cuidado con los longs. Si teneis numeros grandes usad longs. Si no pueden irse a negativos al apsarse del límite y daran enteros. Aunque el problema diga que el número es mas pequeño que 2^32, pensad que a lo mejor estais sumando o multiplicando números.
PYTHON
Si teneis muchos numeros que leer en una sola linea, podeis leerlos todos de golpe y meterlos en una lista con el siguiente numero
numList = list(map(int, input().strip().split()))